51100201441 has 2 divisors, whose sum is σ = 51100201442. Its totient is φ = 51100201440.

The previous prime is 51100201429. The next prime is 51100201501. The reversal of 51100201441 is 14410200115.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 38699151841 + 12401049600 = 196721^2 + 111360^2 .

It is a cyclic number.

It is not a de Polignac number, because 51100201441 - 2¹⁵ = 51100168673 is a prime.

It is a super-2 number, since 2×51100201441² (a number of 22 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (51100201421) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25550100720 + 25550100721.

It is an arithmetic number, because the mean of its divisors is an integer number (25550100721).

Almost surely, 2^51100201441 is an apocalyptic number.

It is an amenable number.

51100201441 is a deficient number, since it is larger than the sum of its proper divisors (1).

51100201441 is an equidigital number, since it uses as much as digits as its factorization.

51100201441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 160, while the sum is 19.

Adding to 51100201441 its reverse (14410200115), we get a palindrome (65510401556).

The spelling of 51100201441 in words is "fifty-one billion, one hundred million, two hundred one thousand, four hundred forty-one".