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5110049939 is a prime number
BaseRepresentation
bin1001100001001010…
…10010110010010011
3111012010110102200212
410300211102302103
540431133044224
62203022034335
7240426464531
oct46045226223
914163412625
105110049939
112192543175
12ba74189ab
136358b08b7
1436694b151
151ed943d0e
hex130952c93

5110049939 has 2 divisors, whose sum is σ = 5110049940. Its totient is φ = 5110049938.

The previous prime is 5110049929. The next prime is 5110049947. The reversal of 5110049939 is 9399400115.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5110049939 is a prime.

It is a super-2 number, since 2×51100499392 = 52225220758147807442, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 5110049896 and 5110049905.

It is not a weakly prime, because it can be changed into another prime (5110049929) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2555024969 + 2555024970.

It is an arithmetic number, because the mean of its divisors is an integer number (2555024970).

Almost surely, 25110049939 is an apocalyptic number.

5110049939 is a deficient number, since it is larger than the sum of its proper divisors (1).

5110049939 is an equidigital number, since it uses as much as digits as its factorization.

5110049939 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 43740, while the sum is 41.

The square root of 5110049939 is about 71484.6133024443. The cubic root of 5110049939 is about 1722.4305302482.

The spelling of 5110049939 in words is "five billion, one hundred ten million, forty-nine thousand, nine hundred thirty-nine".