Base | Representation |
---|---|
bin | 1001100001001010… |
… | …10010110010111001 |
3 | 111012010110102202021 |
4 | 10300211102302321 |
5 | 40431133044402 |
6 | 2203022034441 |
7 | 240426464614 |
oct | 46045226271 |
9 | 14163412667 |
10 | 5110049977 |
11 | 21925431aa |
12 | ba7418a21 |
13 | 6358b0916 |
14 | 36694b17b |
15 | 1ed943d37 |
hex | 130952cb9 |
5110049977 has 2 divisors, whose sum is σ = 5110049978. Its totient is φ = 5110049976.
The previous prime is 5110049947. The next prime is 5110050073. The reversal of 5110049977 is 7799400115.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4344919056 + 765130921 = 65916^2 + 27661^2 .
It is a cyclic number.
It is not a de Polignac number, because 5110049977 - 231 = 2962566329 is a prime.
It is a super-2 number, since 2×51100499772 = 52225221534875401058, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5110049947) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2555024988 + 2555024989.
It is an arithmetic number, because the mean of its divisors is an integer number (2555024989).
Almost surely, 25110049977 is an apocalyptic number.
It is an amenable number.
5110049977 is a deficient number, since it is larger than the sum of its proper divisors (1).
5110049977 is an equidigital number, since it uses as much as digits as its factorization.
5110049977 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 79380, while the sum is 43.
The square root of 5110049977 is about 71484.6135682358. The cubic root of 5110049977 is about 1722.4305345177.
The spelling of 5110049977 in words is "five billion, one hundred ten million, forty-nine thousand, nine hundred seventy-seven".
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