Search a number
-
+
51100543331 = 85959488409
BaseRepresentation
bin101111100101110101…
…000110100101100011
311212220021200120020222
4233211311012211203
51314123214341311
635250353553255
73456214310615
oct574565064543
9155807616228
1051100543331
111a742a195a2
129aa157582b
134a84a80ab6
14268a970db5
1514e12d6adb
hexbe5d46963

51100543331 has 4 divisors (see below), whose sum is σ = 51160032600. Its totient is φ = 51041054064.

The previous prime is 51100543303. The next prime is 51100543363. The reversal of 51100543331 is 13334500115.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-51100543331 is a prime.

It is a super-2 number, since 2×511005433312 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 51100543331.

It is not an unprimeable number, because it can be changed into a prime (51100543381) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29743346 + ... + 29745063.

It is an arithmetic number, because the mean of its divisors is an integer number (12790008150).

Almost surely, 251100543331 is an apocalyptic number.

51100543331 is a deficient number, since it is larger than the sum of its proper divisors (59489269).

51100543331 is an equidigital number, since it uses as much as digits as its factorization.

51100543331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 59489268.

The product of its (nonzero) digits is 2700, while the sum is 26.

The spelling of 51100543331 in words is "fifty-one billion, one hundred million, five hundred forty-three thousand, three hundred thirty-one".

Divisors: 1 859 59488409 51100543331