Base | Representation |
---|---|
bin | 100101001011100011100… |
… | …0100110101111101101110 |
3 | 200002111221120222202200021 |
4 | 1022113013010311331232 |
5 | 1132210343322104132 |
6 | 14511305523352354 |
7 | 1035121644520222 |
oct | 112270704657556 |
9 | 20074846882607 |
10 | 5110056050542 |
11 | 16a0187470233 |
12 | 6a64435226ba |
13 | 2b0b51087571 |
14 | 13948419a782 |
15 | 8cdce6db997 |
hex | 4a5c7135f6e |
5110056050542 has 16 divisors (see below), whose sum is σ = 7703445238272. Its totient is φ = 2542252842360.
The previous prime is 5110056050527. The next prime is 5110056050543. The reversal of 5110056050542 is 2450506500115.
It is a super-3 number, since 3×51100560505423 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 5110056050498 and 5110056050507.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5110056050543) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2105508 + ... + 3827959.
It is an arithmetic number, because the mean of its divisors is an integer number (481465327392).
Almost surely, 25110056050542 is an apocalyptic number.
5110056050542 is a deficient number, since it is larger than the sum of its proper divisors (2593389187730).
5110056050542 is a wasteful number, since it uses less digits than its factorization.
5110056050542 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5935623.
The product of its (nonzero) digits is 30000, while the sum is 34.
The spelling of 5110056050542 in words is "five trillion, one hundred ten billion, fifty-six million, fifty thousand, five hundred forty-two".
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