Base | Representation |
---|---|
bin | 10111001111001111101111… |
… | …01000001101110000111111 |
3 | 20200221020121001202101201002 |
4 | 23213213313220031300333 |
5 | 23144221111342410012 |
6 | 300403352230240515 |
7 | 13522644562563410 |
oct | 1347476750156077 |
9 | 220836531671632 |
10 | 51101380435007 |
11 | 15311a79055361 |
12 | 5893958ab613b |
13 | 2268abb4b95a6 |
14 | c8946a16d807 |
15 | 5d93e68dd7c2 |
hex | 2e79f7a0dc3f |
51101380435007 has 16 divisors (see below), whose sum is σ = 58420021588992. Its totient is φ = 43787352504480.
The previous prime is 51101380434991. The next prime is 51101380435031. The reversal of 51101380435007 is 70053408310115.
It is a cyclic number.
It is not a de Polignac number, because 51101380435007 - 24 = 51101380434991 is a prime.
It is a super-2 number, since 2×511013804350072 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51101380435067) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 294801032 + ... + 294974322.
It is an arithmetic number, because the mean of its divisors is an integer number (3651251349312).
Almost surely, 251101380435007 is an apocalyptic number.
51101380435007 is a deficient number, since it is larger than the sum of its proper divisors (7318641153985).
51101380435007 is a wasteful number, since it uses less digits than its factorization.
51101380435007 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 186358.
The product of its (nonzero) digits is 50400, while the sum is 38.
The spelling of 51101380435007 in words is "fifty-one trillion, one hundred one billion, three hundred eighty million, four hundred thirty-five thousand, seven".
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