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51101606651153 is a prime number
BaseRepresentation
bin10111001111010000001010…
…00111001010010100010001
320200221021011211102100220212
423213220011013022110101
523144222042300314103
6300403430511013505
713522653310436612
oct1347500507122421
9220837154370825
1051101606651153
1115312084813953
125893a0080a295
132268b263224b6
14c8948c217c09
155d940b6c57d8
hex2e7a051ca511

51101606651153 has 2 divisors, whose sum is σ = 51101606651154. Its totient is φ = 51101606651152.

The previous prime is 51101606651141. The next prime is 51101606651171. The reversal of 51101606651153 is 35115660610115.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 27181124456704 + 23920482194449 = 5213552^2 + 4890857^2 .

It is a cyclic number.

It is not a de Polignac number, because 51101606651153 - 224 = 51101589873937 is a prime.

It is a super-2 number, since 2×511016066511532 (a number of 28 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 51101606651153.

It is not a weakly prime, because it can be changed into another prime (51101606651653) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25550803325576 + 25550803325577.

It is an arithmetic number, because the mean of its divisors is an integer number (25550803325577).

Almost surely, 251101606651153 is an apocalyptic number.

It is an amenable number.

51101606651153 is a deficient number, since it is larger than the sum of its proper divisors (1).

51101606651153 is an equidigital number, since it uses as much as digits as its factorization.

51101606651153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 81000, while the sum is 41.

The spelling of 51101606651153 in words is "fifty-one trillion, one hundred one billion, six hundred six million, six hundred fifty-one thousand, one hundred fifty-three".