Base | Representation |
---|---|
bin | 101111100101111010… |
… | …101111001000010001 |
3 | 11212220101110121000121 |
4 | 233211322233020101 |
5 | 1314124104120423 |
6 | 35250445350241 |
7 | 3456233001244 |
oct | 574572571021 |
9 | 155811417017 |
10 | 51102020113 |
11 | 1a743838081 |
12 | 9aa1b68381 |
13 | 4a8517a031 |
14 | 268ac3725b |
15 | 14e14c945d |
hex | be5eaf211 |
51102020113 has 2 divisors, whose sum is σ = 51102020114. Its totient is φ = 51102020112.
The previous prime is 51102020041. The next prime is 51102020119. The reversal of 51102020113 is 31102020115.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 50740716049 + 361304064 = 225257^2 + 19008^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-51102020113 is a prime.
It is a super-2 number, since 2×511020201132 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (51102020119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25551010056 + 25551010057.
It is an arithmetic number, because the mean of its divisors is an integer number (25551010057).
Almost surely, 251102020113 is an apocalyptic number.
It is an amenable number.
51102020113 is a deficient number, since it is larger than the sum of its proper divisors (1).
51102020113 is an equidigital number, since it uses as much as digits as its factorization.
51102020113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 60, while the sum is 16.
Adding to 51102020113 its reverse (31102020115), we get a palindrome (82204040228).
The spelling of 51102020113 in words is "fifty-one billion, one hundred two million, twenty thousand, one hundred thirteen".
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