Base | Representation |
---|---|
bin | 100101001011101000110… |
… | …0001010111110000111001 |
3 | 200002112101210202102100112 |
4 | 1022113101201113300321 |
5 | 1132211223203114202 |
6 | 14511335143514105 |
7 | 1035126203235062 |
oct | 112272141276071 |
9 | 20075353672315 |
10 | 5110231301177 |
11 | 16a0267389672 |
12 | 6a6492158935 |
13 | 2b0b7b487772 |
14 | 13949d579569 |
15 | 8cddeca7b52 |
hex | 4a5d1857c39 |
5110231301177 has 2 divisors, whose sum is σ = 5110231301178. Its totient is φ = 5110231301176.
The previous prime is 5110231301129. The next prime is 5110231301213. The reversal of 5110231301177 is 7711031320115.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4446379518736 + 663851782441 = 2108644^2 + 814771^2 .
It is a cyclic number.
It is not a de Polignac number, because 5110231301177 - 226 = 5110164192313 is a prime.
It is a super-2 number, since 2×51102313011772 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5110231321177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2555115650588 + 2555115650589.
It is an arithmetic number, because the mean of its divisors is an integer number (2555115650589).
Almost surely, 25110231301177 is an apocalyptic number.
It is an amenable number.
5110231301177 is a deficient number, since it is larger than the sum of its proper divisors (1).
5110231301177 is an equidigital number, since it uses as much as digits as its factorization.
5110231301177 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4410, while the sum is 32.
The spelling of 5110231301177 in words is "five trillion, one hundred ten billion, two hundred thirty-one million, three hundred one thousand, one hundred seventy-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.084 sec. • engine limits •