Base | Representation |
---|---|
bin | 101111100110000100… |
… | …000000111101010001 |
3 | 11212220120001011112112 |
4 | 233212010000331101 |
5 | 1314130214434213 |
6 | 35251013435105 |
7 | 3456262451456 |
oct | 574604007521 |
9 | 155816034475 |
10 | 51104452433 |
11 | 1a745149561 |
12 | 9aa293ba95 |
13 | 4a8581c188 |
14 | 268b2ab82d |
15 | 14e1809ea8 |
hex | be6100f51 |
51104452433 has 2 divisors, whose sum is σ = 51104452434. Its totient is φ = 51104452432.
The previous prime is 51104452423. The next prime is 51104452447. The reversal of 51104452433 is 33425440115.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 44036183104 + 7068269329 = 209848^2 + 84073^2 .
It is a cyclic number.
It is not a de Polignac number, because 51104452433 - 24 = 51104452417 is a prime.
It is a super-2 number, since 2×511044524332 (a number of 22 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 51104452433.
It is not a weakly prime, because it can be changed into another prime (51104452423) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25552226216 + 25552226217.
It is an arithmetic number, because the mean of its divisors is an integer number (25552226217).
Almost surely, 251104452433 is an apocalyptic number.
It is an amenable number.
51104452433 is a deficient number, since it is larger than the sum of its proper divisors (1).
51104452433 is an equidigital number, since it uses as much as digits as its factorization.
51104452433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 28800, while the sum is 32.
Adding to 51104452433 its reverse (33425440115), we get a palindrome (84529892548).
The spelling of 51104452433 in words is "fifty-one billion, one hundred four million, four hundred fifty-two thousand, four hundred thirty-three".
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