511049993 has 2 divisors, whose sum is σ = 511049994. Its totient is φ = 511049992.

The previous prime is 511049989. The next prime is 511050019. The reversal of 511049993 is 399940115.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 429815824 + 81234169 = 20732^2 + 9013^2 .

It is a cyclic number.

It is not a de Polignac number, because 511049993 - 2² = 511049989 is a prime.

It is a super-2 number, since 2×511049993² = 522344190690600098, which contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 511049993.

It is not a weakly prime, because it can be changed into another prime (511049963) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 255524996 + 255524997.

It is an arithmetic number, because the mean of its divisors is an integer number (255524997).

Almost surely, 2^511049993 is an apocalyptic number.

It is an amenable number.

511049993 is a deficient number, since it is larger than the sum of its proper divisors (1).

511049993 is an equidigital number, since it uses as much as digits as its factorization.

511049993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 43740, while the sum is 41.

The square root of 511049993 is about 22606.4148639275. The cubic root of 511049993 is about 799.5048983436.

The spelling of 511049993 in words is "five hundred eleven million, forty-nine thousand, nine hundred ninety-three".