Base | Representation |
---|---|
bin | 101111100110000110… |
… | …001001010100111001 |
3 | 11212220121002112202020 |
4 | 233212012021110321 |
5 | 1314130340323001 |
6 | 35251033425053 |
7 | 3456300266112 |
oct | 574606112471 |
9 | 155817075666 |
10 | 51105011001 |
11 | 1a7454a0190 |
12 | 9aa2b6b189 |
13 | 4a859864a5 |
14 | 268b3b5209 |
15 | 14e18ba736 |
hex | be6189539 |
51105011001 has 16 divisors (see below), whose sum is σ = 74459943360. Its totient is φ = 30920491520.
The previous prime is 51105010933. The next prime is 51105011017. The reversal of 51105011001 is 10011050115.
51105011001 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 51105011001 - 226 = 51037902137 is a prime.
It is a super-2 number, since 2×511050110012 (a number of 22 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (51105011071) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1286196 + ... + 1325333.
It is an arithmetic number, because the mean of its divisors is an integer number (4653746460).
Almost surely, 251105011001 is an apocalyptic number.
It is an amenable number.
51105011001 is a deficient number, since it is larger than the sum of its proper divisors (23354932359).
51105011001 is a wasteful number, since it uses less digits than its factorization.
51105011001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2612136.
The product of its (nonzero) digits is 25, while the sum is 15.
Adding to 51105011001 its reverse (10011050115), we get a palindrome (61116061116).
The spelling of 51105011001 in words is "fifty-one billion, one hundred five million, eleven thousand, one".
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