Base | Representation |
---|---|
bin | 100101001011110010011… |
… | …0101010010000101100011 |
3 | 200002120020101101122121001 |
4 | 1022113210311102011203 |
5 | 1132212404123203112 |
6 | 14511431240012431 |
7 | 1035140216126566 |
oct | 112274465220543 |
9 | 20076211348531 |
10 | 5110555287907 |
11 | 16a04132566a3 |
12 | 6a6562761117 |
13 | 2b0c006334a4 |
14 | 1394d05d44dd |
15 | 8ce0d453c57 |
hex | 4a5e4d52163 |
5110555287907 has 2 divisors, whose sum is σ = 5110555287908. Its totient is φ = 5110555287906.
The previous prime is 5110555287899. The next prime is 5110555287923. The reversal of 5110555287907 is 7097825550115.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5110555287907 - 23 = 5110555287899 is a prime.
It is a super-2 number, since 2×51105552879072 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5110555207907) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2555277643953 + 2555277643954.
It is an arithmetic number, because the mean of its divisors is an integer number (2555277643954).
Almost surely, 25110555287907 is an apocalyptic number.
5110555287907 is a deficient number, since it is larger than the sum of its proper divisors (1).
5110555287907 is an equidigital number, since it uses as much as digits as its factorization.
5110555287907 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4410000, while the sum is 55.
The spelling of 5110555287907 in words is "five trillion, one hundred ten billion, five hundred fifty-five million, two hundred eighty-seven thousand, nine hundred seven".
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