Base | Representation |
---|---|
bin | 100101001011110010011… |
… | …0110010010000101010001 |
3 | 200002120020101212222011102 |
4 | 1022113210312102011101 |
5 | 1132212404210100113 |
6 | 14511431245354145 |
7 | 1035140221301033 |
oct | 112274466220521 |
9 | 20076211788142 |
10 | 5110555550033 |
11 | 16a041341562a |
12 | 6a6562868955 |
13 | 2b0c006c58ab |
14 | 1394d0661c53 |
15 | 8ce0d4a6758 |
hex | 4a5e4d92151 |
5110555550033 has 2 divisors, whose sum is σ = 5110555550034. Its totient is φ = 5110555550032.
The previous prime is 5110555550029. The next prime is 5110555550069. The reversal of 5110555550033 is 3300555550115.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 5050190991169 + 60364558864 = 2247263^2 + 245692^2 .
It is a cyclic number.
It is not a de Polignac number, because 5110555550033 - 22 = 5110555550029 is a prime.
It is a super-2 number, since 2×51105555500332 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5110555550003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2555277775016 + 2555277775017.
It is an arithmetic number, because the mean of its divisors is an integer number (2555277775017).
Almost surely, 25110555550033 is an apocalyptic number.
It is an amenable number.
5110555550033 is a deficient number, since it is larger than the sum of its proper divisors (1).
5110555550033 is an equidigital number, since it uses as much as digits as its factorization.
5110555550033 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 140625, while the sum is 38.
The spelling of 5110555550033 in words is "five trillion, one hundred ten billion, five hundred fifty-five million, five hundred fifty thousand, thirty-three".
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