Base | Representation |
---|---|
bin | 100101001011110011110… |
… | …0011101100111101101011 |
3 | 200002120100120102121221211 |
4 | 1022113213203230331223 |
5 | 1132213002324323201 |
6 | 14511435552013551 |
7 | 1035141312562324 |
oct | 112274743547553 |
9 | 20076316377854 |
10 | 5110601011051 |
11 | 16a0437046118 |
12 | 6a6575b312b7 |
13 | 2b0c09c51cc3 |
14 | 1394d66d744b |
15 | 8ce12486651 |
hex | 4a5e78ecf6b |
5110601011051 has 2 divisors, whose sum is σ = 5110601011052. Its totient is φ = 5110601011050.
The previous prime is 5110601011007. The next prime is 5110601011141. The reversal of 5110601011051 is 1501101060115.
5110601011051 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5110601011051 - 29 = 5110601010539 is a prime.
It is a super-2 number, since 2×51106010110512 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5110601011651) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2555300505525 + 2555300505526.
It is an arithmetic number, because the mean of its divisors is an integer number (2555300505526).
Almost surely, 25110601011051 is an apocalyptic number.
5110601011051 is a deficient number, since it is larger than the sum of its proper divisors (1).
5110601011051 is an equidigital number, since it uses as much as digits as its factorization.
5110601011051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 150, while the sum is 22.
Adding to 5110601011051 its reverse (1501101060115), we get a palindrome (6611702071166).
The spelling of 5110601011051 in words is "five trillion, one hundred ten billion, six hundred one million, eleven thousand, fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •