Base | Representation |
---|---|
bin | 10111001111011010010101… |
… | …10000010000101110011011 |
3 | 20200221210021120201021201222 |
4 | 23213231022300100232123 |
5 | 23144314234411124012 |
6 | 300410132554002255 |
7 | 13523235560345264 |
oct | 1347551260205633 |
9 | 220853246637658 |
10 | 51107070020507 |
11 | 15314428739136 |
12 | 5894a8641638b |
13 | 22694b717c127 |
14 | c89849a5796b |
15 | 5d962b15b972 |
hex | 2e7b4ac10b9b |
51107070020507 has 16 divisors (see below), whose sum is σ = 54293411251200. Its totient is φ = 47970426540960.
The previous prime is 51107070020471. The next prime is 51107070020627. The reversal of 51107070020507 is 70502007070115.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 51107070020507 - 212 = 51107070016411 is a prime.
It is a super-3 number, since 3×511070700205073 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (51107070020207) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 38048918 + ... + 39369204.
It is an arithmetic number, because the mean of its divisors is an integer number (3393338203200).
Almost surely, 251107070020507 is an apocalyptic number.
51107070020507 is a deficient number, since it is larger than the sum of its proper divisors (3186341230693).
51107070020507 is a wasteful number, since it uses less digits than its factorization.
51107070020507 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1339106.
The product of its (nonzero) digits is 17150, while the sum is 35.
The spelling of 51107070020507 in words is "fifty-one trillion, one hundred seven billion, seventy million, twenty thousand, five hundred seven".
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