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51110005123 is a prime number
BaseRepresentation
bin101111100110011001…
…001100100110000011
311212220221111021101201
4233212121030212003
51314133130130443
635251332442031
73456360606202
oct574631144603
9155827437351
1051110005123
111a7482a1361
129aa4779317
134a86a146a8
14268bd15239
1514e205534d
hexbe664c983

51110005123 has 2 divisors, whose sum is σ = 51110005124. Its totient is φ = 51110005122.

The previous prime is 51110005097. The next prime is 51110005127. The reversal of 51110005123 is 32150001115.

51110005123 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 51110005123 - 25 = 51110005091 is a prime.

It is a super-2 number, since 2×511100051232 (a number of 22 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 51110005123.

It is not a weakly prime, because it can be changed into another prime (51110005127) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25555002561 + 25555002562.

It is an arithmetic number, because the mean of its divisors is an integer number (25555002562).

Almost surely, 251110005123 is an apocalyptic number.

51110005123 is a deficient number, since it is larger than the sum of its proper divisors (1).

51110005123 is an equidigital number, since it uses as much as digits as its factorization.

51110005123 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 150, while the sum is 19.

Adding to 51110005123 its reverse (32150001115), we get a palindrome (83260006238).

The spelling of 51110005123 in words is "fifty-one billion, one hundred ten million, five thousand, one hundred twenty-three".