Base | Representation |
---|---|
bin | 101111100110011001… |
… | …010111100010110011 |
3 | 11212220221120112220202 |
4 | 233212121113202303 |
5 | 1314133133044341 |
6 | 35251333425415 |
7 | 3456361154021 |
oct | 574631274263 |
9 | 155827515822 |
10 | 51110049971 |
11 | 1a748322022 |
12 | 9aa479b26b |
13 | 4a86a2bc26 |
14 | 268bd27711 |
15 | 14e206379b |
hex | be66578b3 |
51110049971 has 2 divisors, whose sum is σ = 51110049972. Its totient is φ = 51110049970.
The previous prime is 51110049961. The next prime is 51110050049. The reversal of 51110049971 is 17994001115.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 51110049971 - 210 = 51110048947 is a prime.
It is a super-2 number, since 2×511100499712 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (51110049911) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25555024985 + 25555024986.
It is an arithmetic number, because the mean of its divisors is an integer number (25555024986).
Almost surely, 251110049971 is an apocalyptic number.
51110049971 is a deficient number, since it is larger than the sum of its proper divisors (1).
51110049971 is an equidigital number, since it uses as much as digits as its factorization.
51110049971 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11340, while the sum is 38.
The spelling of 51110049971 in words is "fifty-one billion, one hundred ten million, forty-nine thousand, nine hundred seventy-one".
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