Base | Representation |
---|---|
bin | 1001100001010001… |
… | …11011111101101001 |
3 | 111012012020221211201 |
4 | 10300220323331221 |
5 | 40431404130113 |
6 | 2203054324201 |
7 | 240440553211 |
oct | 46050737551 |
9 | 14165227751 |
10 | 5111005033 |
11 | 2193035802 |
12 | ba77b9661 |
13 | 635b56544 |
14 | 366b19241 |
15 | 1eda81cdd |
hex | 130a3bf69 |
5111005033 has 2 divisors, whose sum is σ = 5111005034. Its totient is φ = 5111005032.
The previous prime is 5111004947. The next prime is 5111005091. The reversal of 5111005033 is 3305001115.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4688414784 + 422590249 = 68472^2 + 20557^2 .
It is a cyclic number.
It is not a de Polignac number, because 5111005033 - 217 = 5110873961 is a prime.
It is a super-2 number, since 2×51110050332 = 52244744894702662178, which contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 5111005033.
It is not a weakly prime, because it can be changed into another prime (5111305033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2555502516 + 2555502517.
It is an arithmetic number, because the mean of its divisors is an integer number (2555502517).
Almost surely, 25111005033 is an apocalyptic number.
It is an amenable number.
5111005033 is a deficient number, since it is larger than the sum of its proper divisors (1).
5111005033 is an equidigital number, since it uses as much as digits as its factorization.
5111005033 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 225, while the sum is 19.
The square root of 5111005033 is about 71491.2934069597. The cubic root of 5111005033 is about 1722.5378338691.
Adding to 5111005033 its reverse (3305001115), we get a palindrome (8416006148).
The spelling of 5111005033 in words is "five billion, one hundred eleven million, five thousand, thirty-three".
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