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51110404041 = 3311979277703
BaseRepresentation
bin101111100110011010…
…101101111111001001
311212220222020112121110
4233212122231333021
51314133230412131
635251345200533
73456364160214
oct574632557711
9155828215543
1051110404041
111a748544044
129aa4930149
134a86b24138
14268bdba77b
1514e20d3646
hexbe66adfc9

51110404041 has 16 divisors (see below), whose sum is σ = 70381301760. Its totient is φ = 32957673360.

The previous prime is 51110404039. The next prime is 51110404087. The reversal of 51110404041 is 14040401115.

It is not a de Polignac number, because 51110404041 - 21 = 51110404039 is a prime.

It is a super-2 number, since 2×511104040412 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 51110403999 and 51110404017.

It is not an unprimeable number, because it can be changed into a prime (51110404441) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 45196 + ... + 322898.

It is an arithmetic number, because the mean of its divisors is an integer number (4398831360).

Almost surely, 251110404041 is an apocalyptic number.

It is an amenable number.

51110404041 is a deficient number, since it is larger than the sum of its proper divisors (19270897719).

51110404041 is a wasteful number, since it uses less digits than its factorization.

51110404041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 279716.

The product of its (nonzero) digits is 320, while the sum is 21.

Adding to 51110404041 its reverse (14040401115), we get a palindrome (65150805156).

The spelling of 51110404041 in words is "fifty-one billion, one hundred ten million, four hundred four thousand, forty-one".

Divisors: 1 3 31 93 1979 5937 61349 184047 277703 833109 8608793 25826379 549574237 1648722711 17036801347 51110404041