Base | Representation |
---|---|
bin | 101111100110011010… |
… | …110101101000011001 |
3 | 11212220222022010120011 |
4 | 233212122311220121 |
5 | 1314133232412403 |
6 | 35251350001521 |
7 | 3456364350415 |
oct | 574632655031 |
9 | 155828263504 |
10 | 51110435353 |
11 | 1a74856561a |
12 | 9aa49462a1 |
13 | 4a86b35473 |
14 | 268bdc7d45 |
15 | 14e20dca6d |
hex | be66b5a19 |
51110435353 has 2 divisors, whose sum is σ = 51110435354. Its totient is φ = 51110435352.
The previous prime is 51110435333. The next prime is 51110435359. The reversal of 51110435353 is 35353401115.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 42204360969 + 8906074384 = 205437^2 + 94372^2 .
It is a cyclic number.
It is not a de Polignac number, because 51110435353 - 213 = 51110427161 is a prime.
It is a super-2 number, since 2×511104353532 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (51110435359) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25555217676 + 25555217677.
It is an arithmetic number, because the mean of its divisors is an integer number (25555217677).
Almost surely, 251110435353 is an apocalyptic number.
It is an amenable number.
51110435353 is a deficient number, since it is larger than the sum of its proper divisors (1).
51110435353 is an equidigital number, since it uses as much as digits as its factorization.
51110435353 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13500, while the sum is 31.
Adding to 51110435353 its reverse (35353401115), we get a palindrome (86463836468).
The spelling of 51110435353 in words is "fifty-one billion, one hundred ten million, four hundred thirty-five thousand, three hundred fifty-three".
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