Base | Representation |
---|---|
bin | 111010000110110010000100… |
… | …0110100000000101001000111 |
3 | 2111000200012202122010212122010 |
4 | 1310031210020310000221013 |
5 | 1013442423132031340033 |
6 | 5011010352042305303 |
7 | 212441105006332050 |
oct | 16415441064005107 |
9 | 2430605678125563 |
10 | 511105551043143 |
11 | 138943713084741 |
12 | 493a781aab8233 |
13 | 18c2607b670294 |
14 | 902d8d7d95727 |
15 | 3e150657e5863 |
hex | 1d0d908d00a47 |
511105551043143 has 16 divisors (see below), whose sum is σ = 778838426827776. Its totient is φ = 292056219703200.
The previous prime is 511105551043141. The next prime is 511105551043169. The reversal of 511105551043143 is 341340155501115.
It is not a de Polignac number, because 511105551043143 - 21 = 511105551043141 is a prime.
It is a super-2 number, since 2×5111055510431432 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (511105551043141) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 169098783 + ... + 172094768.
It is an arithmetic number, because the mean of its divisors is an integer number (48677401676736).
Almost surely, 2511105551043143 is an apocalyptic number.
511105551043143 is a deficient number, since it is larger than the sum of its proper divisors (267732875784633).
511105551043143 is a wasteful number, since it uses less digits than its factorization.
511105551043143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 341264894.
The product of its (nonzero) digits is 90000, while the sum is 39.
The spelling of 511105551043143 in words is "five hundred eleven trillion, one hundred five billion, five hundred fifty-one million, forty-three thousand, one hundred forty-three".
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