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5111252444132 = 222998074262119
BaseRepresentation
bin100101001100000111001…
…1000101110001111100100
3200002122000222012212010222
41022120032120232033210
51132220321111203012
614512024342303512
71035163412635202
oct112301630561744
920078028185128
105111252444132
1116a074083346a
126a6718127b98
132b0cb1bb8373
1413955902c072
158ce4e763972
hex4a60e62e3e4

5111252444132 has 12 divisors (see below), whose sum is σ = 8944723710720. Its totient is φ = 2555617098216.

The previous prime is 5111252444083. The next prime is 5111252444159. The reversal of 5111252444132 is 2314442521115.

It is a super-2 number, since 2×51112524441322 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 5111252444092 and 5111252444101.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 931832 + ... + 3330287.

It is an arithmetic number, because the mean of its divisors is an integer number (745393642560).

Almost surely, 25111252444132 is an apocalyptic number.

It is an amenable number.

5111252444132 is a deficient number, since it is larger than the sum of its proper divisors (3833471266588).

5111252444132 is a wasteful number, since it uses less digits than its factorization.

5111252444132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4561930 (or 4561928 counting only the distinct ones).

The product of its digits is 38400, while the sum is 35.

Adding to 5111252444132 its reverse (2314442521115), we get a palindrome (7425694965247).

The spelling of 5111252444132 in words is "five trillion, one hundred eleven billion, two hundred fifty-two million, four hundred forty-four thousand, one hundred thirty-two".

Divisors: 1 2 4 299807 599614 1199228 4262119 8524238 17048476 1277813111033 2555626222066 5111252444132