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51113031532 = 2294583135101
BaseRepresentation
bin101111100110100100…
…101111011101101100
311212221011012000211221
4233212210233131230
51314134414002112
635251521353124
73456425412433
oct574644573554
9155834160757
1051113031532
111a749a79122
129aa57987a4
134a87534074
14268c4a211a
1514e2451e07
hexbe692f76c

51113031532 has 12 divisors (see below), whose sum is σ = 89449412976. Its totient is φ = 25556056400.

The previous prime is 51113031517. The next prime is 51113031533. The reversal of 51113031532 is 23513031115.

It is a super-2 number, since 2×511130315322 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 51113031497 and 51113031506.

It is not an unprimeable number, because it can be changed into a prime (51113031533) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 310782 + ... + 445882.

It is an arithmetic number, because the mean of its divisors is an integer number (7454117748).

Almost surely, 251113031532 is an apocalyptic number.

It is an amenable number.

51113031532 is a deficient number, since it is larger than the sum of its proper divisors (38336381444).

51113031532 is a wasteful number, since it uses less digits than its factorization.

51113031532 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 229688 (or 229686 counting only the distinct ones).

The product of its (nonzero) digits is 1350, while the sum is 25.

Adding to 51113031532 its reverse (23513031115), we get a palindrome (74626062647).

The spelling of 51113031532 in words is "fifty-one billion, one hundred thirteen million, thirty-one thousand, five hundred thirty-two".

Divisors: 1 2 4 94583 135101 189166 270202 378332 540404 12778257883 25556515766 51113031532