511132514201131 has 2 divisors, whose sum is σ = 511132514201132. Its totient is φ = 511132514201130.

The previous prime is 511132514201069. The next prime is 511132514201137. The reversal of 511132514201131 is 131102415231115.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 511132514201131 - 2³⁷ = 510995075247659 is a prime.

It is a super-2 number, since 2×511132514201131² (a number of 30 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 511132514201093 and 511132514201102.

It is not a weakly prime, because it can be changed into another prime (511132514201137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 255566257100565 + 255566257100566.

It is an arithmetic number, because the mean of its divisors is an integer number (255566257100566).

Almost surely, 2^{511132514201131} is an apocalyptic number.

511132514201131 is a deficient number, since it is larger than the sum of its proper divisors (1).

511132514201131 is an equidigital number, since it uses as much as digits as its factorization.

511132514201131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3600, while the sum is 31.

Adding to 511132514201131 its reverse (131102415231115), we get a palindrome (642234929432246).

The spelling of 511132514201131 in words is "five hundred eleven trillion, one hundred thirty-two billion, five hundred fourteen million, two hundred one thousand, one hundred thirty-one".