Base | Representation |
---|---|
bin | 100101001100001001010… |
… | …1110101111000010001011 |
3 | 200002122020001100111201020 |
4 | 1022120102232233002023 |
5 | 1132220443240322103 |
6 | 14512035504323523 |
7 | 1035165256253205 |
oct | 112302256570213 |
9 | 20078201314636 |
10 | 5111325323403 |
11 | 16a0778990772 |
12 | 6a67386135a3 |
13 | 2b0cc40245b0 |
14 | 13956499d775 |
15 | 8ce55d5c753 |
hex | 4a612baf08b |
5111325323403 has 16 divisors (see below), whose sum is σ = 7415002219296. Its totient is φ = 3113003842560.
The previous prime is 5111325323393. The next prime is 5111325323413. The reversal of 5111325323403 is 3043235231115.
It is an interprime number because it is at equal distance from previous prime (5111325323393) and next prime (5111325323413).
It is not a de Polignac number, because 5111325323403 - 222 = 5111321129099 is a prime.
It is a super-2 number, since 2×51113253234032 (a number of 26 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (5111325323413) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 675561288 + ... + 675568853.
It is an arithmetic number, because the mean of its divisors is an integer number (463437638706).
Almost surely, 25111325323403 is an apocalyptic number.
5111325323403 is a deficient number, since it is larger than the sum of its proper divisors (2303676895893).
5111325323403 is a wasteful number, since it uses less digits than its factorization.
5111325323403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1351130254.
The product of its (nonzero) digits is 32400, while the sum is 33.
The spelling of 5111325323403 in words is "five trillion, one hundred eleven billion, three hundred twenty-five million, three hundred twenty-three thousand, four hundred three".
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