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5111340132401 is a prime number
BaseRepresentation
bin100101001100001001110…
…0111001110100000110001
3200002122021002012212211122
41022120103213032200301
51132221011033214101
614512041153552025
71035165526162136
oct112302347164061
920078232185748
105111340132401
1116a0786285a08
126a6741575615
132b0cc710b009
1413956693658d
158ce572d551b
hex4a6139ce831

5111340132401 has 2 divisors, whose sum is σ = 5111340132402. Its totient is φ = 5111340132400.

The previous prime is 5111340132391. The next prime is 5111340132413. The reversal of 5111340132401 is 1042310431115.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4669315939600 + 442024192801 = 2160860^2 + 664849^2 .

It is a cyclic number.

It is not a de Polignac number, because 5111340132401 - 234 = 5094160263217 is a prime.

It is a super-2 number, since 2×51113401324012 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (5111340332401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2555670066200 + 2555670066201.

It is an arithmetic number, because the mean of its divisors is an integer number (2555670066201).

Almost surely, 25111340132401 is an apocalyptic number.

It is an amenable number.

5111340132401 is a deficient number, since it is larger than the sum of its proper divisors (1).

5111340132401 is an equidigital number, since it uses as much as digits as its factorization.

5111340132401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 26.

Adding to 5111340132401 its reverse (1042310431115), we get a palindrome (6153650563516).

The spelling of 5111340132401 in words is "five trillion, one hundred eleven billion, three hundred forty million, one hundred thirty-two thousand, four hundred one".