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5111401040332 = 2210611204382903
BaseRepresentation
bin100101001100001011100…
…1111100100100111001100
3200002122102022211022210221
41022120113033210213030
51132221122131242312
614512051211241124
71035200165660236
oct112302717444714
920078368738727
105111401040332
1116a08076a6a44
126a6759a491a4
132b1006915302
14139570a6d256
158ce5c817207
hex4a6173e49cc

5111401040332 has 12 divisors (see below), whose sum is σ = 8953382508336. Its totient is φ = 2553291752240.

The previous prime is 5111401040303. The next prime is 5111401040359. The reversal of 5111401040332 is 2330401041115.

It is a super-2 number, since 2×51114010403322 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 5111401040297 and 5111401040306.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 602187208 + ... + 602195695.

It is an arithmetic number, because the mean of its divisors is an integer number (746115209028).

Almost surely, 25111401040332 is an apocalyptic number.

It is an amenable number.

5111401040332 is a deficient number, since it is larger than the sum of its proper divisors (3841981468004).

5111401040332 is a wasteful number, since it uses less digits than its factorization.

5111401040332 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1204383968 (or 1204383966 counting only the distinct ones).

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 5111401040332 its reverse (2330401041115), we get a palindrome (7441802081447).

The spelling of 5111401040332 in words is "five trillion, one hundred eleven billion, four hundred one million, forty thousand, three hundred thirty-two".

Divisors: 1 2 4 1061 2122 4244 1204382903 2408765806 4817531612 1277850260083 2555700520166 5111401040332