Base | Representation |
---|---|
bin | 100101001100001011100… |
… | …1111100100111010010011 |
3 | 200002122102022211101111020 |
4 | 1022120113033210322103 |
5 | 1132221122131312210 |
6 | 14512051211250523 |
7 | 1035200165663634 |
oct | 112302717447223 |
9 | 20078368741436 |
10 | 5111401041555 |
11 | 16a08076a7956 |
12 | 6a6759a49a43 |
13 | 2b1006915a33 |
14 | 139570a6d88b |
15 | 8ce5c817770 |
hex | 4a6173e4e93 |
5111401041555 has 16 divisors (see below), whose sum is σ = 8180188504224. Its totient is φ = 2725431609600.
The previous prime is 5111401041521. The next prime is 5111401041613. The reversal of 5111401041555 is 5551401041115.
5111401041555 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 5111401041555 - 230 = 5110327299731 is a prime.
It is a super-2 number, since 2×51114010415552 (a number of 26 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 40494004 + ... + 40620033.
It is an arithmetic number, because the mean of its divisors is an integer number (511261781514).
Almost surely, 25111401041555 is an apocalyptic number.
5111401041555 is a deficient number, since it is larger than the sum of its proper divisors (3068787462669).
5111401041555 is a wasteful number, since it uses less digits than its factorization.
5111401041555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 81118246.
The product of its (nonzero) digits is 10000, while the sum is 33.
The spelling of 5111401041555 in words is "five trillion, one hundred eleven billion, four hundred one million, forty-one thousand, five hundred fifty-five".
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