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511144529113 is a prime number
BaseRepresentation
bin1110111000000101001…
…01101000110011011001
31210212100112121110011001
413130002211220303121
531333310444412423
61030452213105001
751633431545021
oct7340245506331
91725315543131
10511144529113
11187858841139
1283091328161
133927bcaa0ba
141aa4d396a81
15d469220cad
hex7702968cd9

511144529113 has 2 divisors, whose sum is σ = 511144529114. Its totient is φ = 511144529112.

The previous prime is 511144529101. The next prime is 511144529149. The reversal of 511144529113 is 311925441115.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 403037061904 + 108107467209 = 634852^2 + 328797^2 .

It is a cyclic number.

It is not a de Polignac number, because 511144529113 - 25 = 511144529081 is a prime.

It is a super-2 number, since 2×5111445291132 (a number of 24 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (511144520113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 255572264556 + 255572264557.

It is an arithmetic number, because the mean of its divisors is an integer number (255572264557).

Almost surely, 2511144529113 is an apocalyptic number.

It is an amenable number.

511144529113 is a deficient number, since it is larger than the sum of its proper divisors (1).

511144529113 is an equidigital number, since it uses as much as digits as its factorization.

511144529113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 21600, while the sum is 37.

The spelling of 511144529113 in words is "five hundred eleven billion, one hundred forty-four million, five hundred twenty-nine thousand, one hundred thirteen".