Base | Representation |
---|---|
bin | 10111001111101111111000… |
… | …00011101010000001110011 |
3 | 20200222220010112112010122101 |
4 | 23213313330003222001303 |
5 | 23200011430424403312 |
6 | 300415324311121231 |
7 | 13524125263613113 |
oct | 1347677403520163 |
9 | 220886115463571 |
10 | 51118634606707 |
11 | 15319322636998 |
12 | 5897173373217 |
13 | 226a60b053145 |
14 | c8a2258d3043 |
15 | 5d9aa6570a57 |
hex | 2e7dfc0ea073 |
51118634606707 has 8 divisors (see below), whose sum is σ = 51248587433120. Its totient is φ = 50988743187840.
The previous prime is 51118634606687. The next prime is 51118634606759. The reversal of 51118634606707 is 70760643681115.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 51118634606707 - 215 = 51118634573939 is a prime.
It is a super-2 number, since 2×511186346067072 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (51118634606807) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 13684644 + ... + 17014897.
It is an arithmetic number, because the mean of its divisors is an integer number (6406073429140).
Almost surely, 251118634606707 is an apocalyptic number.
51118634606707 is a deficient number, since it is larger than the sum of its proper divisors (129952826413).
51118634606707 is a wasteful number, since it uses less digits than its factorization.
51118634606707 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 30703773.
The product of its (nonzero) digits is 5080320, while the sum is 55.
The spelling of 51118634606707 in words is "fifty-one trillion, one hundred eighteen billion, six hundred thirty-four million, six hundred six thousand, seven hundred seven".
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