Search a number
-
+
511201262017 is a prime number
BaseRepresentation
bin1110111000001011111…
…10000011100111000001
31210212111111100210001201
413130011332003213001
531333420010341032
61030502001101201
751635021014045
oct7340576034701
91725444323051
10511201262017
11187887870436
12830a8327801
133928a981c74
141aa56b24025
15d46e1ca8e7
hex7705f839c1

511201262017 has 2 divisors, whose sum is σ = 511201262018. Its totient is φ = 511201262016.

The previous prime is 511201262009. The next prime is 511201262023. The reversal of 511201262017 is 710262102115.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 510037360561 + 1163901456 = 714169^2 + 34116^2 .

It is a cyclic number.

It is not a de Polignac number, because 511201262017 - 23 = 511201262009 is a prime.

It is a super-2 number, since 2×5112012620172 (a number of 24 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (511201262057) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 255600631008 + 255600631009.

It is an arithmetic number, because the mean of its divisors is an integer number (255600631009).

Almost surely, 2511201262017 is an apocalyptic number.

It is an amenable number.

511201262017 is a deficient number, since it is larger than the sum of its proper divisors (1).

511201262017 is an equidigital number, since it uses as much as digits as its factorization.

511201262017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1680, while the sum is 28.

The spelling of 511201262017 in words is "five hundred eleven billion, two hundred one million, two hundred sixty-two thousand, seventeen".