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51120662953 = 373371369169
BaseRepresentation
bin101111100111000001…
…110110100110101001
311212221200112202012011
4233213001312212221
51314143342203303
635252353115521
73456550315453
oct574701664651
9155850482164
1051120662953
111a753310788
129aa8258ba1
134a88ca67b9
14268d4cb2d3
1514e2e5d16d
hexbe70769a9

51120662953 has 4 divisors (see below), whose sum is σ = 51122069460. Its totient is φ = 51119256448.

The previous prime is 51120662941. The next prime is 51120662963. The reversal of 51120662953 is 35926602115.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 12694078224 + 38426584729 = 112668^2 + 196027^2 .

It is a cyclic number.

It is not a de Polignac number, because 51120662953 - 229 = 50583792041 is a prime.

It is a super-2 number, since 2×511206629532 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (51120662963) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 647248 + ... + 721921.

It is an arithmetic number, because the mean of its divisors is an integer number (12780517365).

Almost surely, 251120662953 is an apocalyptic number.

It is an amenable number.

51120662953 is a deficient number, since it is larger than the sum of its proper divisors (1406507).

51120662953 is a wasteful number, since it uses less digits than its factorization.

51120662953 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1406506.

The product of its (nonzero) digits is 97200, while the sum is 40.

The spelling of 51120662953 in words is "fifty-one billion, one hundred twenty million, six hundred sixty-two thousand, nine hundred fifty-three".

Divisors: 1 37337 1369169 51120662953