Base | Representation |
---|---|
bin | 100101001100100001011… |
… | …1001000000111010100011 |
3 | 200002201022100202012202222 |
4 | 1022121002321000322203 |
5 | 1132224122112340301 |
6 | 14512252010501255 |
7 | 1035224300202326 |
oct | 112310271007243 |
9 | 20081270665688 |
10 | 5112133324451 |
11 | 16a1052a9692a |
12 | 6a692313482b |
13 | 2b10c254921a |
14 | 13960000c7bd |
15 | 8cea1c6531b |
hex | 4a642e40ea3 |
5112133324451 has 2 divisors, whose sum is σ = 5112133324452. Its totient is φ = 5112133324450.
The previous prime is 5112133324411. The next prime is 5112133324513. The reversal of 5112133324451 is 1544233312115.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5112133324451 - 26 = 5112133324387 is a prime.
It is a super-2 number, since 2×51121333244512 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5112133324411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2556066662225 + 2556066662226.
It is an arithmetic number, because the mean of its divisors is an integer number (2556066662226).
Almost surely, 25112133324451 is an apocalyptic number.
5112133324451 is a deficient number, since it is larger than the sum of its proper divisors (1).
5112133324451 is an equidigital number, since it uses as much as digits as its factorization.
5112133324451 is an evil number, because the sum of its binary digits is even.
The product of its digits is 43200, while the sum is 35.
Adding to 5112133324451 its reverse (1544233312115), we get a palindrome (6656366636566).
The spelling of 5112133324451 in words is "five trillion, one hundred twelve billion, one hundred thirty-three million, three hundred twenty-four thousand, four hundred fifty-one".
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