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5112135500323 = 11345240137171
BaseRepresentation
bin100101001100100001100…
…0001010100001000100011
3200002201022111211202111211
41022121003001110020203
51132224123142002243
614512252125250551
71035224324534065
oct112310301241043
920081274752454
105112135500323
1116a1054242675
126a6923a03a57
132b10c2b2b717
14139600417735
158cea2044d9d
hex4a643054223

5112135500323 has 4 divisors (see below), whose sum is σ = 5157375637608. Its totient is φ = 5066895363040.

The previous prime is 5112135500293. The next prime is 5112135500333. The reversal of 5112135500323 is 3230055312115.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5112135500323 - 25 = 5112135500291 is a prime.

It is a super-2 number, since 2×51121355003232 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5112135500333) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22620068473 + ... + 22620068698.

It is an arithmetic number, because the mean of its divisors is an integer number (1289343909402).

Almost surely, 25112135500323 is an apocalyptic number.

5112135500323 is a deficient number, since it is larger than the sum of its proper divisors (45240137285).

5112135500323 is a wasteful number, since it uses less digits than its factorization.

5112135500323 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 45240137284.

The product of its (nonzero) digits is 13500, while the sum is 31.

The spelling of 5112135500323 in words is "five trillion, one hundred twelve billion, one hundred thirty-five million, five hundred thousand, three hundred twenty-three".

Divisors: 1 113 45240137171 5112135500323