Base | Representation |
---|---|
bin | 100101001100100001101… |
… | …1000011011110101000011 |
3 | 200002201022221020200102002 |
4 | 1022121003120123311003 |
5 | 1132224131214424110 |
6 | 14512252503214215 |
7 | 1035224430206126 |
oct | 112310330336503 |
9 | 20081287220362 |
10 | 5112141561155 |
11 | 16a1057702222 |
12 | 6a6925a4736b |
13 | 2b10c4171305 |
14 | 1396011543bd |
15 | 8cea2840aa5 |
hex | 4a64361bd43 |
5112141561155 has 16 divisors (see below), whose sum is σ = 6216753628800. Its totient is φ = 4035238058880.
The previous prime is 5112141561113. The next prime is 5112141561221. The reversal of 5112141561155 is 5511651412115.
It is not a de Polignac number, because 5112141561155 - 210 = 5112141560131 is a prime.
It is a super-3 number, since 3×51121415611553 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 19493336 + ... + 19753845.
It is an arithmetic number, because the mean of its divisors is an integer number (388547101800).
Almost surely, 25112141561155 is an apocalyptic number.
5112141561155 is a deficient number, since it is larger than the sum of its proper divisors (1104612067645).
5112141561155 is a wasteful number, since it uses less digits than its factorization.
5112141561155 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 39247534.
The product of its digits is 30000, while the sum is 38.
The spelling of 5112141561155 in words is "five trillion, one hundred twelve billion, one hundred forty-one million, five hundred sixty-one thousand, one hundred fifty-five".
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