Base | Representation |
---|---|
bin | 100101001100100001101… |
… | …1111111010010011101011 |
3 | 200002201100001221020211001 |
4 | 1022121003133322103223 |
5 | 1132224132220133003 |
6 | 14512253013215431 |
7 | 1035224452651021 |
oct | 112310337722353 |
9 | 20081301836731 |
10 | 5112143521003 |
11 | 16a1058820732 |
12 | 6a6926631577 |
13 | 2b10c46a939c |
14 | 139601504711 |
15 | 8cea2acb61d |
hex | 4a6437fa4eb |
5112143521003 has 2 divisors, whose sum is σ = 5112143521004. Its totient is φ = 5112143521002.
The previous prime is 5112143520931. The next prime is 5112143521013. The reversal of 5112143521003 is 3001253412115.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5112143521003 - 217 = 5112143389931 is a prime.
It is a super-2 number, since 2×51121435210032 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5112143521013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2556071760501 + 2556071760502.
It is an arithmetic number, because the mean of its divisors is an integer number (2556071760502).
Almost surely, 25112143521003 is an apocalyptic number.
5112143521003 is a deficient number, since it is larger than the sum of its proper divisors (1).
5112143521003 is an equidigital number, since it uses as much as digits as its factorization.
5112143521003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3600, while the sum is 28.
Adding to 5112143521003 its reverse (3001253412115), we get a palindrome (8113396933118).
The spelling of 5112143521003 in words is "five trillion, one hundred twelve billion, one hundred forty-three million, five hundred twenty-one thousand, three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •