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51122450051 is a prime number
BaseRepresentation
bin101111100111001000…
…101010111010000011
311212221210220112121222
4233213020222322003
51314144321400201
635252455305255
73456601440611
oct574710527203
9155853815558
1051122450051
111a754321422
129aa897b22b
134a8948105a
14268d8346b1
1514e31b291b
hexbe722ae83

51122450051 has 2 divisors, whose sum is σ = 51122450052. Its totient is φ = 51122450050.

The previous prime is 51122450033. The next prime is 51122450063. The reversal of 51122450051 is 15005422115.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-51122450051 is a prime.

It is a super-2 number, since 2×511224500512 (a number of 22 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 51122450051.

It is not a weakly prime, because it can be changed into another prime (51122450551) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25561225025 + 25561225026.

It is an arithmetic number, because the mean of its divisors is an integer number (25561225026).

Almost surely, 251122450051 is an apocalyptic number.

51122450051 is a deficient number, since it is larger than the sum of its proper divisors (1).

51122450051 is an equidigital number, since it uses as much as digits as its factorization.

51122450051 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2000, while the sum is 26.

Adding to 51122450051 its reverse (15005422115), we get a palindrome (66127872166).

The spelling of 51122450051 in words is "fifty-one billion, one hundred twenty-two million, four hundred fifty thousand, fifty-one".