5112251102041 has 2 divisors, whose sum is σ = 5112251102042. Its totient is φ = 5112251102040.

The previous prime is 5112251102033. The next prime is 5112251102131. The reversal of 5112251102041 is 1402011522115.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4988839412041 + 123411690000 = 2233571^2 + 351300^2 .

It is a cyclic number.

It is not a de Polignac number, because 5112251102041 - 2³ = 5112251102033 is a prime.

It is a super-2 number, since 2×5112251102041² (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 5112251101997 and 5112251102015.

It is not a weakly prime, because it can be changed into another prime (5112251105041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2556125551020 + 2556125551021.

It is an arithmetic number, because the mean of its divisors is an integer number (2556125551021).

Almost surely, 2^{5112251102041} is an apocalyptic number.

It is an amenable number.

5112251102041 is a deficient number, since it is larger than the sum of its proper divisors (1).

5112251102041 is an equidigital number, since it uses as much as digits as its factorization.

5112251102041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 800, while the sum is 25.

Adding to 5112251102041 its reverse (1402011522115), we get a palindrome (6514262624156).

The spelling of 5112251102041 in words is "five trillion, one hundred twelve billion, two hundred fifty-one million, one hundred two thousand, forty-one".