Base | Representation |
---|---|
bin | 1001100001011011… |
… | …10111101000111011 |
3 | 111012021200122111222 |
4 | 10300231313220323 |
5 | 40432222014133 |
6 | 2203142142255 |
7 | 240454550006 |
oct | 46055675073 |
9 | 14167618458 |
10 | 5112298043 |
11 | 2193839206 |
12 | ba812198b |
13 | 6361b9c38 |
14 | 366d7453d |
15 | 1edc39e98 |
hex | 130b77a3b |
5112298043 has 2 divisors, whose sum is σ = 5112298044. Its totient is φ = 5112298042.
The previous prime is 5112298019. The next prime is 5112298049. The reversal of 5112298043 is 3408922115.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5112298043 - 212 = 5112293947 is a prime.
It is a super-2 number, since 2×51122980432 = 52271182560923259698, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5112297994 and 5112298012.
It is not a weakly prime, because it can be changed into another prime (5112298049) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2556149021 + 2556149022.
It is an arithmetic number, because the mean of its divisors is an integer number (2556149022).
Almost surely, 25112298043 is an apocalyptic number.
5112298043 is a deficient number, since it is larger than the sum of its proper divisors (1).
5112298043 is an equidigital number, since it uses as much as digits as its factorization.
5112298043 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 17280, while the sum is 35.
The square root of 5112298043 is about 71500.3359642457. The cubic root of 5112298043 is about 1722.6830806347.
The spelling of 5112298043 in words is "five billion, one hundred twelve million, two hundred ninety-eight thousand, forty-three".
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