Base | Representation |
---|---|
bin | 100101001100100110100… |
… | …0100000111000001010001 |
3 | 200002201202020220200202020 |
4 | 1022121031010013001101 |
5 | 1132224444311131301 |
6 | 14512320545042053 |
7 | 1035231442025001 |
oct | 112311504070121 |
9 | 20081666820666 |
10 | 5112304005201 |
11 | 16a11303738a8 |
12 | 6a6970326329 |
13 | 2b111ba09353 |
14 | 13961895c001 |
15 | 8ceb1c2c436 |
hex | 4a64d107051 |
5112304005201 has 32 divisors (see below), whose sum is σ = 6884524889088. Its totient is φ = 3374306994240.
The previous prime is 5112304005181. The next prime is 5112304005227. The reversal of 5112304005201 is 1025004032115.
It is a happy number.
It is not a de Polignac number, because 5112304005201 - 210 = 5112304004177 is a prime.
It is a super-2 number, since 2×51123040052012 (a number of 26 digits) contains 22 as substring.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (5112304009201) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 708955486 + ... + 708962696.
It is an arithmetic number, because the mean of its divisors is an integer number (215141402784).
Almost surely, 25112304005201 is an apocalyptic number.
It is an amenable number.
5112304005201 is a deficient number, since it is larger than the sum of its proper divisors (1772220883887).
5112304005201 is a wasteful number, since it uses less digits than its factorization.
5112304005201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12581.
The product of its (nonzero) digits is 1200, while the sum is 24.
Adding to 5112304005201 its reverse (1025004032115), we get a palindrome (6137308037316).
The spelling of 5112304005201 in words is "five trillion, one hundred twelve billion, three hundred four million, five thousand, two hundred one".
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