Base | Representation |
---|---|
bin | 101111100111001011… |
… | …011101000111100001 |
3 | 11212221212021121221011 |
4 | 233213023131013201 |
5 | 1314200013230001 |
6 | 35252523100521 |
7 | 3456610601005 |
oct | 574713350741 |
9 | 155855247834 |
10 | 51123180001 |
11 | 1a75477a893 |
12 | 9aa9071741 |
13 | 4a8967838a |
14 | 268d984705 |
15 | 14e32a8d51 |
hex | be72dd1e1 |
51123180001 has 2 divisors, whose sum is σ = 51123180002. Its totient is φ = 51123180000.
The previous prime is 51123179993. The next prime is 51123180013. The reversal of 51123180001 is 10008132115.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 44988531025 + 6134648976 = 212105^2 + 78324^2 .
It is a cyclic number.
It is not a de Polignac number, because 51123180001 - 23 = 51123179993 is a prime.
It is a super-2 number, since 2×511231800012 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (51123180401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25561590000 + 25561590001.
It is an arithmetic number, because the mean of its divisors is an integer number (25561590001).
Almost surely, 251123180001 is an apocalyptic number.
It is an amenable number.
51123180001 is a deficient number, since it is larger than the sum of its proper divisors (1).
51123180001 is an equidigital number, since it uses as much as digits as its factorization.
51123180001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 240, while the sum is 22.
The spelling of 51123180001 in words is "fifty-one billion, one hundred twenty-three million, one hundred eighty thousand, one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •