Base | Representation |
---|---|
bin | 100101001100101001101… |
… | …1110010111011001111001 |
3 | 200002202000202021121100001 |
4 | 1022121103132113121321 |
5 | 1132230204324120403 |
6 | 14512335350113001 |
7 | 1035234216116431 |
oct | 112312336273171 |
9 | 20082022247301 |
10 | 5112411551353 |
11 | 16a1186049917 |
12 | 6a69a034b761 |
13 | 2b1138092822 |
14 | 139628d552c1 |
15 | 8cebb3c2c1d |
hex | 4a653797679 |
5112411551353 has 8 divisors (see below), whose sum is σ = 5117678254080. Its totient is φ = 5107146283200.
The previous prime is 5112411551339. The next prime is 5112411551371. The reversal of 5112411551353 is 3531551142115.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5112411551353 is a prime.
It is a super-2 number, since 2×51124115513532 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5112411551333) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6846868 + ... + 7556746.
It is an arithmetic number, because the mean of its divisors is an integer number (639709781760).
Almost surely, 25112411551353 is an apocalyptic number.
It is an amenable number.
5112411551353 is a deficient number, since it is larger than the sum of its proper divisors (5266702727).
5112411551353 is a wasteful number, since it uses less digits than its factorization.
5112411551353 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 717287.
The product of its digits is 45000, while the sum is 37.
Adding to 5112411551353 its reverse (3531551142115), we get a palindrome (8643962693468).
The spelling of 5112411551353 in words is "five trillion, one hundred twelve billion, four hundred eleven million, five hundred fifty-one thousand, three hundred fifty-three".
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