5112412131 has 4 divisors (see below), whose sum is σ = 6816549512. Its totient is φ = 3408274752.

The previous prime is 5112412121. The next prime is 5112412133. The reversal of 5112412131 is 1312142115.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 5112412131 - 2⁷ = 5112412003 is a prime.

It is a super-2 number, since 2×5112412131² = 52273515594391922322, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 5112412098 and 5112412107.

It is not an unprimeable number, because it can be changed into a prime (5112412133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 852068686 + ... + 852068691.

It is an arithmetic number, because the mean of its divisors is an integer number (1704137378).

Almost surely, 2^5112412131 is an apocalyptic number.

5112412131 is a deficient number, since it is larger than the sum of its proper divisors (1704137381).

5112412131 is a wasteful number, since it uses less digits than its factorization.

5112412131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1704137380.

The product of its digits is 240, while the sum is 21.

The square root of 5112412131 is about 71501.1337742277. The cubic root of 5112412131 is about 1722.6958952244.

Adding to 5112412131 its reverse (1312142115), we get a palindrome (6424554246).

The spelling of 5112412131 in words is "five billion, one hundred twelve million, four hundred twelve thousand, one hundred thirty-one".