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51124341041 is a prime number
BaseRepresentation
bin101111100111001111…
…111000100100110001
311212221221110121120122
4233213033320210301
51314200312403131
635253004020025
73456623504654
oct574717704461
9155857417518
1051124341041
111a7553a3124
129aa9531615
134a89993997
14268dba789b
1514e3437d7b
hexbe73f8931

51124341041 has 2 divisors, whose sum is σ = 51124341042. Its totient is φ = 51124341040.

The previous prime is 51124341007. The next prime is 51124341049. The reversal of 51124341041 is 14014342115.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 44531550625 + 6592790416 = 211025^2 + 81196^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-51124341041 is a prime.

It is a super-2 number, since 2×511243410412 (a number of 22 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 51124341041.

It is not a weakly prime, because it can be changed into another prime (51124341049) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25562170520 + 25562170521.

It is an arithmetic number, because the mean of its divisors is an integer number (25562170521).

Almost surely, 251124341041 is an apocalyptic number.

It is an amenable number.

51124341041 is a deficient number, since it is larger than the sum of its proper divisors (1).

51124341041 is an equidigital number, since it uses as much as digits as its factorization.

51124341041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1920, while the sum is 26.

Adding to 51124341041 its reverse (14014342115), we get a palindrome (65138683156).

The spelling of 51124341041 in words is "fifty-one billion, one hundred twenty-four million, three hundred forty-one thousand, forty-one".