51124354051 has 4 divisors (see below), whose sum is σ = 51175023400. Its totient is φ = 51073684704.

The previous prime is 51124354027. The next prime is 51124354079. The reversal of 51124354051 is 15045342115.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 51124354051 - 2⁵ = 51124354019 is a prime.

It is a super-2 number, since 2×51124354051² (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (51124354451) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25333161 + ... + 25335178.

It is an arithmetic number, because the mean of its divisors is an integer number (12793755850).

Almost surely, 2^51124354051 is an apocalyptic number.

51124354051 is a deficient number, since it is larger than the sum of its proper divisors (50669349).

51124354051 is a wasteful number, since it uses less digits than its factorization.

51124354051 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 50669348.

The product of its (nonzero) digits is 12000, while the sum is 31.

Adding to 51124354051 its reverse (15045342115), we get a palindrome (66169696166).

The spelling of 51124354051 in words is "fifty-one billion, one hundred twenty-four million, three hundred fifty-four thousand, fifty-one".