Base | Representation |
---|---|
bin | 10111001111111100000001… |
… | …10100101010111100101110 |
3 | 20201000111222002120211020120 |
4 | 23213332000310222330232 |
5 | 23200113310143442332 |
6 | 300422323425025410 |
7 | 13524446023305534 |
oct | 1347760064527456 |
9 | 221014862524216 |
10 | 51125157015342 |
11 | 1532106a33a053 |
12 | 5898493785266 |
13 | 226b10a41b837 |
14 | c8a683c4c154 |
15 | 5d9d38e9b32c |
hex | 2e7f80d2af2e |
51125157015342 has 16 divisors (see below), whose sum is σ = 102619448741712. Its totient is φ = 16980196553280.
The previous prime is 51125157015277. The next prime is 51125157015371. The reversal of 51125157015342 is 24351075152115.
It is a super-2 number, since 2×511251570153422 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 51125157015294 and 51125157015303.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 15380611159 + ... + 15380614482.
It is an arithmetic number, because the mean of its divisors is an integer number (6413715546357).
Almost surely, 251125157015342 is an apocalyptic number.
51125157015342 is an abundant number, since it is smaller than the sum of its proper divisors (51494291726370).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
51125157015342 is a wasteful number, since it uses less digits than its factorization.
51125157015342 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 30761225923.
The product of its (nonzero) digits is 210000, while the sum is 42.
The spelling of 51125157015342 in words is "fifty-one trillion, one hundred twenty-five billion, one hundred fifty-seven million, fifteen thousand, three hundred forty-two".
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