Base | Representation |
---|---|
bin | 100101001100101101100… |
… | …1001001011100000010001 |
3 | 200002202100201101102002220 |
4 | 1022121123021023200101 |
5 | 1132230440243342223 |
6 | 14512400223531253 |
7 | 1035240340544136 |
oct | 112313311134021 |
9 | 20082321342086 |
10 | 5112540215313 |
11 | 16a1241738a73 |
12 | 6a6a17459b29 |
13 | 2b115893114b |
14 | 13963c08858d |
15 | 8cec783a6e3 |
hex | 4a65b24b811 |
5112540215313 has 8 divisors (see below), whose sum is σ = 6823995339168. Its totient is φ = 3404722617504.
The previous prime is 5112540215273. The next prime is 5112540215323. The reversal of 5112540215313 is 3135120452115.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 5112540215313 - 29 = 5112540214801 is a prime.
It is a super-2 number, since 2×51125402153132 (a number of 26 digits) contains 22 as substring.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (5112540215323) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 909378231 + ... + 909383852.
It is an arithmetic number, because the mean of its divisors is an integer number (852999417396).
Almost surely, 25112540215313 is an apocalyptic number.
It is an amenable number.
5112540215313 is a deficient number, since it is larger than the sum of its proper divisors (1711455123855).
5112540215313 is a wasteful number, since it uses less digits than its factorization.
5112540215313 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1818763023.
The product of its (nonzero) digits is 18000, while the sum is 33.
Adding to 5112540215313 its reverse (3135120452115), we get a palindrome (8247660667428).
The spelling of 5112540215313 in words is "five trillion, one hundred twelve billion, five hundred forty million, two hundred fifteen thousand, three hundred thirteen".
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