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511255323552131 is a prime number
BaseRepresentation
bin111010000111110111110011…
…1111100110010100110000011
32111001012112100112112122111122
41310033233213330302212003
51014002401400312132011
65011203241523102455
7212454656343550154
oct16417574774624603
92431175315478448
10511255323552131
111389a118a823494
1249410859511a2b
1318c37229a5b472
149036c6544992b
153e18dce43a3db
hex1d0fbe7f32983

511255323552131 has 2 divisors, whose sum is σ = 511255323552132. Its totient is φ = 511255323552130.

The previous prime is 511255323552053. The next prime is 511255323552161. The reversal of 511255323552131 is 131255323552115.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 511255323552131 - 218 = 511255323289987 is a prime.

It is a super-2 number, since 2×5112553235521312 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (511255323552161) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 255627661776065 + 255627661776066.

It is an arithmetic number, because the mean of its divisors is an integer number (255627661776066).

Almost surely, 2511255323552131 is an apocalyptic number.

511255323552131 is a deficient number, since it is larger than the sum of its proper divisors (1).

511255323552131 is an equidigital number, since it uses as much as digits as its factorization.

511255323552131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 675000, while the sum is 44.

The spelling of 511255323552131 in words is "five hundred eleven trillion, two hundred fifty-five billion, three hundred twenty-three million, five hundred fifty-two thousand, one hundred thirty-one".