Base | Representation |
---|---|
bin | 10111001111111100110100… |
… | …10000001111110101001011 |
3 | 20201000120001211102100211222 |
4 | 23213332122100033311023 |
5 | 23200120143410042244 |
6 | 300422434025512255 |
7 | 13524462423663422 |
oct | 1347763220176513 |
9 | 221016054370758 |
10 | 51125583674699 |
11 | 15321269163596 |
12 | 589859264268b |
13 | 226b1779356b1 |
14 | c8a6c47922b9 |
15 | 5d9d61678bee |
hex | 2e7f9a40fd4b |
51125583674699 has 2 divisors, whose sum is σ = 51125583674700. Its totient is φ = 51125583674698.
The previous prime is 51125583674689. The next prime is 51125583674707. The reversal of 51125583674699 is 99647638552115.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 51125583674699 - 232 = 51121288707403 is a prime.
It is a super-2 number, since 2×511255836746992 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (51125583674689) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25562791837349 + 25562791837350.
It is an arithmetic number, because the mean of its divisors is an integer number (25562791837350).
Almost surely, 251125583674699 is an apocalyptic number.
51125583674699 is a deficient number, since it is larger than the sum of its proper divisors (1).
51125583674699 is an equidigital number, since it uses as much as digits as its factorization.
51125583674699 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 489888000, while the sum is 71.
The spelling of 51125583674699 in words is "fifty-one trillion, one hundred twenty-five billion, five hundred eighty-three million, six hundred seventy-four thousand, six hundred ninety-nine".
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